When fertilization occurs between two
true-breeding parents that differ in
only one characteristic, the process is called a monohybrid cross, and the resulting offspring are monohybrids. Mendel performed seven monohybrid
crosses involving contrasting traits for each characteristic. On the basis of his results in F1 and F2 generations, Mendel postulated that each
parent in the monohybrid cross contributed one of two paired unit factors to each offspring, and every possible
combination of unit factors was
equally likely.
To
demonstrate a monohybrid cross, consider the case of true-breeding pea plants with yellow versus
green pea seeds. The dominant seed color is yellow; therefore, the parental genotypes
were YY for the plants with yellow seeds and yy for the plants with green seeds,
respectively. A Punnett square, devised
by the British geneticist Reginald Punnett, can be drawn that applies the rules
of probability to predict the possible outcomes of a genetic cross or mating
and their expected frequencies. To
prepare a Punnett square, all possible combinations of the parental alleles are
listed along the top (for one parent) and side (for the other parent) of a
grid, representing their meiotic segregation into haploid gametes. Then the
combinations of egg and sperm are made in the boxes in the table to show which
alleles are combining. Each box then represents the diploid genotype of a zygote, or fertilized egg, that could result from this mating. Because each possibility
is equally likely, genotypic ratios
can be determined from a Punnett square. If the pattern of inheritance
(dominant or recessive) is known, the phenotypic ratios can be inferred as
well. For a monohybrid cross of two true-breeding parents, each parent
contributes one type of allele. In this case, only one genotype is possible.
All offspring are Yy and have yellow seeds (Figure 1).
Figure 1 In the P generation, pea
plants
that are true-breeding for the dominant yellow phenotype are crossed with plants with
the recessive green phenotype. This cross produces F1
heterozygotes with a yellow
phenotype. Punnett square analysis
can be used to predict the genotypes of the F2
generation.
A self-cross of one of the Yy heterozygous offspring can be represented in a 2 × 2 Punnett square because each parent
can donate one of two different
alleles. Therefore, the offspring
can potentially have one of four allele combinations: YY, Yy, yY,
or yy (Figure 1). Notice that there are two ways to obtain the Yy genotype: a Y from the egg
and a y from the sperm, or a y from the egg and a Y from the sperm. Both of these
possibilities must be counted. Recall that Mendel’s pea- plant characteristics behaved
in the same way in reciprocal crosses.
Therefore, the two possible heterozygous combinations produce offspring
that are genotypically and phenotypically identical despite their dominant and
recessive alleles deriving from different
parents. They are grouped together.
Because fertilization is a random event, we expect each combination to be equally
likely and for the offspring to exhibit a ratio of YY:Yy:yy genotypes of 1:2:1 (Figure 1). Furthermore, because the YY and Yy offspring have yellow seeds
and are phenotypically identical, applying the sum rule of probability, we expect the offspring to exhibit a phenotypic ratio of 3 yellow:1 green.
Indeed, working with large sample
sizes, Mendel observed approximately this
ratio in every F2 generation resulting from
crosses for individual traits.
Mendel validated these
results by performing an F3 cross in which he
self-crossed the dominant- and recessive-expressing F2 plants.
When he self-crossed the plants expressing green seeds, all of the offspring had green seeds, confirming that
all green seeds had homozygous genotypes of yy.
When he self-crossed the F2 plants expressing
yellow seeds, he found that one-third of the plants bred true, and two-thirds of the plants segregated at a 3:1 ratio of yellow:green seeds. In this case,
the true-breeding plants
had homozygous (YY) genotypes, whereas the segregating plants corresponded to the heterozygous (Yy) genotype. When these plants self-fertilized, the outcome was just
like the F1 self-fertilizing cross.
The Test Cross Distinguishes the Dominant Phenotype
Beyond predicting the offspring of a cross between known homozygous or heterozygous parents,
Mendel also developed a way to determine whether an organism that expressed a dominant trait
was a heterozygote or a homozygote. Called the test cross, this
technique is still used by plant and animal breeders. In a test cross, the
dominant-expressing organism is
crossed with an organism
that is homozygous recessive for the same characteristic. If the dominant-expressing organism is a
homozygote, then all F1 offspring will be heterozygotes expressing
the dominant trait (Figure 2). Alternatively,
if the dominant expressing organism
is a heterozygote, the F1 offspring will exhibit a 1:1 ratio of
heterozygotes and recessive homozygotes (Figure
2). The test cross further validates Mendel’s postulate that pairs of unit factors segregate equally.
Figure 2 A test cross can
be performed to
determine whether an organism expressing
a dominant trait is a homozygote
or a heterozygote.
In
pea plants, round peas (R) are dominant to wrinkled peas (r). You do a test cross between
a pea plant with wrinkled peas (genotype rr) and
a plant of unknown genotype that has round peas. You end up with three plants,
all which have
round peas. From this data, can
you tell if the round
pea parent plant is homozygous dominant or
heterozygous? If the round pea parent plant is heterozygous, what is the probability that a random sample of
3 progeny peas will all
be round?
Many
human diseases are genetically inherited. A healthy person in a family in which some members suffer from a recessive genetic disorder may want to
know if he or she has the disease-causing gene and what risk exists of passing
the disorder on to his or her offspring. Of course, doing
a test cross in humans
is unethical and impractical. Instead,
geneticists use pedigree analysis to study the inheritance pattern
of human genetic diseases (Figure 3).
Figure 3 Alkaptonuria is a recessive genetic
disorder in which two amino
acids,
phenylalanine and
tyrosine, are not properly metabolized. Affected
individuals may have
darkened skin and brown urine,
and may suffer joint damage and other complications. In this pedigree, individuals with the disorder are indicated in blue and have the genotype aa. Unaffected individuals are indicated in yellow and
have
the genotype AA or Aa. Note that it is often possible to
determine a person’s genotype
from the genotype of
their offspring.
For example, if neither
parent has the disorder but their child does, they must be heterozygous.
Two individuals on the pedigree have
an unaffected
phenotype but unknown genotype. Because they do not have the disorder, they must have at least
one
normal allele, so their genotype
gets the “A?” designation.